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[ryabinkin]

How it is possible to substitute one version of shared library to another(older) one for a single program?
I have a program which requires older version of glibc library than I have installed in my system. Of course, I have a file, containing old version of glibc. But I don't want make simbolic link every time I want to run program. It would be better to have more convenient way to do this. For instance, redefine environment variable, which leads to the real location of old library.

What do you think about it? Suggestions are welcome.

Linux RH 9.0
libc version 2.3.2 (GLIBC 2.1)
location /lib/i686

require at least
libc version 2.4.1 (GLIBC 2.0)

[AlexanderK]

Ж

[ryabinkin]

-

[and3008]

-

[ryabinkin]

But how does it possible to do!
I have executable binary and I suppose, it is impossible to change anything inside. So, I ask: Does some variable really exist (for overriden) in the program's enviroment or every program has own pattern of obtaining libraries paths.
In other words, Does universal and common mechanism to determine the location of library exist?
And if "Yes", how is it possible to interact with it? Or every programmer uses the own pattern?

[dmvl]

Попробуй
export LD_LIBRARY_PATH=/path_to_library;
command_to_run

Есть статья по этой теме: http://www.opennet.ru/docs/HOWTO/Program-Library-HOWTO/share d-libraries.html

[ryabinkin]

Thanks for all for suggestions! But, it's a pity, program is still not woking... Too many overridens are needed to be done and also they conflict...